Math, asked by chetandamade9, 8 months ago

the greatest number which on dividing 1659 and 2036 leaves remainder 8 and 4 respectively is

Answers

Answered by harendrachoubay
57

The required number is "127".

Step-by-step explanation:

We have,

Required number = H.C.F. of (1659 - 8) and (2036 - 4)

= 1651 and 2032

∴ Required number = H.C.F. of 1651 and 2032

1651  = 13 × 127 and

2032 = 2 × 2 × 2 × 2 × 127

H.C.F. of 1651 and 2032 = 127

Hence, the required number is "127".

Answered by mohmmadkhan521752
12

Answer:

the greatest number which on dividing 1659 and 2036 leaves remainder 8 and 4 respectively is 127

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