the greatest number which on dividing 1659 and 2036 leaves remainder 8 and 4 respectively is
Answers
Answered by
57
The required number is "127".
Step-by-step explanation:
We have,
Required number = H.C.F. of (1659 - 8) and (2036 - 4)
= 1651 and 2032
∴ Required number = H.C.F. of 1651 and 2032
1651 = 13 × 127 and
2032 = 2 × 2 × 2 × 2 × 127
∴ H.C.F. of 1651 and 2032 = 127
Hence, the required number is "127".
Answered by
12
Answer:
the greatest number which on dividing 1659 and 2036 leaves remainder 8 and 4 respectively is 127
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