The greatest number whose sum of the digits in ones place and hundred place is 5 and the sum of the digits in tens and thousands place is 6.Digits should not be repeated
Answers
Step-by-step explanation:
Digit in hundreds's place=2
Digit in ones' place=2x2=4
Digit in thousands' place=0
Digit in ten-thousands'place=2+4=6
Digit in tens place=6−1=5
∴ The number =60254
The number is 6401.
The highest number that can be placed should be toward the left in order for a number to be biggest.
In light of this, the sum of the digits in the tens and thousands place is six, and the sum of the digits in the one place and hundreds space is five.
The maximum number under the circumstances must be found.
The answer is 5, hence the digit in the hundreds place must be 4 and the one in the ones position must be 1, according to the question.
The sum of the digits in the thousands and tens places is six.
Thus, the digit in the thousand place must be 6, while the digit in the tens place must be 0.
the number is therefore 6401.
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