The greatest possible acceleration or deceleration a train may have in a and its maximum speed is v. Find
the minimum time in which the train can get from one station to the next station, if the total distance is s.
a) s/a +1
b) s/v + v/a
c) s/v +1
d) None of above
Answers
Answered by
5
Answer:
The greatest acceleration or deceleration that a train may have is a . The minimum time in which the train can go from one station to the next at a distance S is. ... 2aS . B ... There is no limit on the speed of the train, so minimum time will be when the train ...
Explanation:
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Answered by
0
Answer:
Explanation:
There is no limit on the speed of the train, so minimum time will be when the train will accelerate for
2
T
and deaccelerate for
2
T
.
So time taken will calculated by S=ut+
2
1
at
2
, where u=0, displacement=
2
S
,time=
2
T
, same distance will be covered while acceleration as well as deacceleration.
So T=2
a
S
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