Physics, asked by vyasvishva29, 9 months ago

The greatest possible acceleration or deceleration a train may have in a and its maximum speed is v. Find
the minimum time in which the train can get from one station to the next station, if the total distance is s.
a) s/a +1
b) s/v + v/a
c) s/v +1
d) None of above​

Answers

Answered by ranahridanshu
5

Answer:

The greatest acceleration or deceleration that a train may have is a . The minimum time in which the train can go from one station to the next at a distance S is. ... 2aS​ ​. B ... There is no limit on the speed of the train, so minimum time will be when the train ...

Explanation:

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Answered by itzlisa91331
0

Answer:

Explanation:

There is no limit on the speed of the train, so minimum time will be when the train will accelerate for  

2

T

​  

 and deaccelerate for  

2

T

​  

.

So time taken will calculated by S=ut+  

2

1

​  

at  

2

, where u=0, displacement=  

2

S

​  

,time=  

2

T

​  

, same distance will be covered while acceleration as well as deacceleration.

So T=2  

a

S

​  

 

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