Math, asked by kumarabhishek76542, 5 hours ago

The greatest value of y, for which 13y4y4 is divisible by 3 is​

Answers

Answered by chocolateboy66
0

Step-by-step explanation:

Solution

Correct option is

B

13

We have our number =2345a60b

And that is divisible by 3 and 5.

We know from divisibility rule of 5 that any number is divisible by 5 if that have end digit 0 or 5. Therefore,

b can only 0 or 5 but we want to find value of a+b is maximum so we take b=5 ( As at b=0 we do not get maximum value of a+b )

So , Now our number is =2345a605

We know from divisibility rule of 3 that if sum of digits of a number is divisible by 3 then the number is also divisible by 3. So,

2+3+4+5+a+6+0+5=25+a

We can have number greater than 25 and divisible by are 27,30,33

So,

a can be =2,5,8 , Here highest number is =8.

Then , we get a=8 and b=5

Therefore,

Maximum value of a+b=8+5=13

Hence, the maximum value of a+b is 13.

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