Question

The greatest5 - digit

number that divides 47 and 87
leaving 7 as remainder in each case is
(a) 40
(b) 15
(c) 30
(d) 60​

Answer 1

47 - 7 = 40

87 - 7 = 80

H.C.F = 40

Therefore, the number is 40

Answer 2

Answer:

40

Step-by-step explanation:

To find:

The greatest 5-digit number that divides 47 and 87 leaving remainder 7 in each case.

• For finding the number, at first we need to subtract 7 from the given numbers.

$47 - 7 = 40 \\ 87 - 7 = 80$

• After then, we need to find the HCF of the two numbers. And the required number is the answer.

Solution:

HCF of 40 and 80 = 40

Hence, 40 is the answer.