Question

The grenade flies horizontally at a speed of 10m/s. The grenade breaks in two parts. The larger fragment, whose mass is 60% of the mass of the entire grenade, continues to move in the same direction at a speed of 25m/s. Find the value and direction of the velocity of the fragment.

Answer 1

Answer:

-12.5 m/s

Explanation:

Let the mass of grenade be M.

mass of larger fragment M1= 60M/100 = 6M/10

mass of smaller fragment M2= 4M/10

velocity of grenade v = 10m/s

velocity of larger fragment v1 = 25m/s

velocity of smaller fragment v2 = ?

Since this explosion (breaking of grenade) is not by any external force, The total liner momentum remains conserved.

Momentum before breaking = Momentum after b.

Mv = 6Mv1/10 + 4Mv2/10

Mv = (2M/10)(3v1 + 2v2)

5v = 3v1 + 2v2

50 = 75 + 2v2

v2 = -25/2

v2 = -12.5 m/s

Velocity of the fragment is -12.5 m/s. It moves in the opposite direction.