Question

The ground state electronic configuration of an element of atomic number 47 is

A) [Kr] 4d9
5s2 B) [Xe] 4d10 5s1 C) [Kr] 4d10 5s1 D) [Kr] 4d6 5s2
5p3​

Answer 1

Answer:

silver :1s2, 2s2, 2p6, 3s2, 3p6, 3d10, 4s2, 4p6, 4d10, 5s1