Question

The ground state energy of hydrogen atom is -13.6 eV. What are the kinetic and potential energies of electron in this state? ​

Answer 1

Explanation:

PE∣/2=T.E∣=K.E

3.4=kE

So, kinetic energy K.E=3.4 eV

Potential energy P.E=−2×∣T.E∣=−2×(3.4)=−6.8 eV

Answer 2

Explanation:

The total energy of an electron in the first excited state of the hydrogen atom is about – 3.4 eV. ... (a) The quoted value of E = – 3.4 eV is based on the customary choice of zero of potential energy at infinity. From the above result of E = – Ek, the kinetic energy of electron in this state is + 3.4 eV.

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