Physics, asked by girijeshwar15193, 6 months ago

the ground state energy of hydrogen atom is -13.6eV, if an electron make a transition from an energy level -0.85 eV, calculate the wavelength of the spectral line emitted. to which series of hudrogen spectrum does this wavelength belong? ​

Answers

Answered by ramsmedicine
0

Answer: 6

Explanation:

From the n  

th

 state, the electron may go to (n−1)  

th

 state, ...., 2nd state or 1st state. So there are (n 1) possible transitions starting from the n  

th

 state. The atoms reaching (n−1)  

th

 state may make (n 2) different transitions. The atoms reaching (n−2)  

th

 state may make (n 3) different transitions. Similarly for other lower states. During each transition a photon with energy hν and wavelength λ is emitted out. Hence, the total number of possible transitions is equal to the number of photons emitted. The total number of possible transitions is

(n−1),(n−2),(n−3),................,3,2,1=  

2

n(n−1)

​  

 

Therefore, for transition of an electron from higher energy state n = 4 to lower energy state n = 1 the number of photons emitted are

2

n(n−1)

​  

=  

2

4(4−1)

​  

=  

2

12

​  

=6

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Answered by amoghnasa
2

Answer:

Hope the pic i attached below helps you!!

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