Chemistry, asked by shraddhabhure6906, 11 months ago

The ground state energy of hydrogen atom is -13.6eV the energy of second excited state of He+ ion is

Answers

Answered by flashkid

4

Answer:

pe= -13.6 Z^2 / n^2

Explanation:

here,for He^ Z=2

n=1 (2-1=1electron)

hence,pe=-54.4 ev

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