Physics, asked by Mrkerhin603, 11 months ago

The ground state energy of the hydrogen atom is 13.6 ev the energy of the second excited state is

Answers

Answered by hariommaurya97
2

energy of electron in hydrogen atom in ground state is -13.6 eV

En=-z^2 13.6 /n^2. electron volt.

energy level is higher than ground energy state in an atom is called as excited energy state level

energy energy of electron in second excited state it means

Z=1,N=3

on substituting this value in equation first

En=-(1)^2×13.6/3^2 electron volt

En=-1×13.6/9

En=-1.5 electron volt

energy of the electron in the second excited state in hydrogen atom is-1.5 electron volt

hope it helps ❤️ ❤️ you

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