Question

The group of bits 101001 is serially shifted (LSB first) into a 6-bit parallel output shift register with an initial state 011110. After fifth clock pulses, the register contains ?

Answer 1

Answer:

thu he be happy he he he be rh

Answer 2

Given:

Initial state = 011110

No. of clock pules = 5

To find:

Register value after five pules.

Solution:

Invert the LSB and feedback to MSB.

Initial state - 011110

First clock pulse - 101111

Second clock pulse - 010111

Third clock pulse - 001011

Fourth clock pulse - 000101

Fifth clock pulse - 000010

After the fifth clock pulse, the register contains 000010.