Math, asked by kirankashyap0666, 1 month ago

The Gryphondoors and the Slitheries were playing a series of magikabaddi, with the first team to get four wins winning the trophy. Magikabaddi is a game with no draws or forfeits, so each session has a clear winner. How many ways are there that the series could be won?​

Answers

Answered by amitnrw
3

Given : The Gryphondoors and the Slitheries were playing a series of magikabaddi, with the first team to get four wins winning the trophy. Magikabaddi is a game with no draws or forfeits, so each session has a clear winner.

To Find : How many ways are there that the series could be won

Solution:

Minimum 4 matches or maximum 7 matches required

Either Gryphondoors wins or Slitheries wins 4 Games

Gryphondoors  wins in 4 games ( 1st 4 games)   = 1 Ways

Gryphondoors  wins in 5 games => (  5th game ) and 3 games in 1st 4

= ⁴C₃ = 4 ways

Gryphondoors  wins in 6 games => (  6th game ) and 3 games in 1st 5

= ⁵C₃ = 10 ways

Gryphondoors  wins in 7 games => (  7th game ) and 3 games in 1st 6

= ⁶C₃ = 20 ways

Total ways Gryphondoors wins  = 1 + 4 + 10 + 20  = 35

Similarly Slitheries wins in 35 ways

Total Ways = 35 + 35 = 70

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