Math, asked by gujjar3777, 9 months ago

The H.C.F and L.C.M of two numbers are 11 and 385 respectively. If one number lies between 75 and 125 , then that number is ?​

Answers

Answered by BRAINLYARMY001
1

Answer:

hi

your answer is here !

Step-by-step explanation:

Product of numbers = 11 x 385 = 4235

Let the numbers be 11a and 11b . Then , 11a x 11b = 4235 => ab = 35

Now, co-primes with product 35 are (1,35) and (5,7)

So, the numbers are ( 11 x 1, 11 x 35) and (11 x 5, 11 x 7)

Since one number lies 75 and 125, the suitable pair is (55,77)

Hence , required number = 77

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Answered by vbhai97979
0

Answer:

MARK ME BRAINLIEST

Step-by-step explanation:

385÷11=35 and 35 =5×7 , 5 and 7 are prime numbers ,

so two numbers are 11×5 =55 and 11×7 = 77

within 75 and 125 the number is 77 is to be considered our ans

so ans is 77

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