The H.C.F and L.C.M of two numbers are 11 and 385 respectively. If one number lies between 75 and 125 , then that number is ?
Answers
Answered by
1
Answer:
hi
your answer is here !
Step-by-step explanation:
Product of numbers = 11 x 385 = 4235
Let the numbers be 11a and 11b . Then , 11a x 11b = 4235 => ab = 35
Now, co-primes with product 35 are (1,35) and (5,7)
So, the numbers are ( 11 x 1, 11 x 35) and (11 x 5, 11 x 7)
Since one number lies 75 and 125, the suitable pair is (55,77)
Hence , required number = 77
follow me !
Answered by
0
Answer:
MARK ME BRAINLIEST
Step-by-step explanation:
385÷11=35 and 35 =5×7 , 5 and 7 are prime numbers ,
so two numbers are 11×5 =55 and 11×7 = 77
within 75 and 125 the number is 77 is to be considered our ans
so ans is 77
Similar questions