Question

The H.C.F. and L.C.M.
of two numbers is 128.
and 14976 respectively.
If one of the number is
1152, find the other number.​

Answer 1

Hi there !!

H.C.F = 128

L.C.M = 14,976

We know that,

L.CM × HCF = Product of two numbers

Let Y be the other number.

128 ×14,976 = 1152 × y

$\frac{1916928}{1152} = 1664$

Hence, other number will 1664.

We can easily verify our answer-

L.CM × HCF = Product of two numbers

128 ×14,976 = 1152 × y (put y= 1664)

128 ×14,976 = 1152 ×1664

1,916,928=1,916,928

Thankyou :)

Answer 2

The H.C.F. and L.C.M. of two numbers is 128 and 14976 respectively.

• H.C.F. = 128

• L.C.M. = 14976

Now..

Product of two numbers = L.C.M. × H.C.F.

=> 128 × 14976

Also it is given that one number is 1152.

Then, let other number be M.

=> M × 1152 = 128 × 14976

=> M = $\dfrac{128 \: \times \: 14976}{1152}$

=> M = $\dfrac{1916928}{1152}$

=> M = 1664

______________________________

Other number = M = 1664

___________ [ANSWER]

☞ Product of two numbers = L.C.M. × H.C.F.

Two numbers are : 1152 and 1164

So,

=> 1152 × 1164 = 128 × 14976

=> 1916928 = 1916928

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