Math, asked by saffari045, 2 days ago

the h.c.f of 14xy2, 28z3y2, 7xy2z is

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Answered by 9a212komal
1

Answer:

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Answered by TakshMehta99
0

Answer:

hcf of 14xy2=4,28z3y2= 24,7cy2z=14=4+24++14=42 is hcf

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