Math, asked by maheshsuresh299, 4 months ago

The H.C.F of 4a4b4c?,8a%bc3
and 16a'b'c is
4a'b'c?
O
16a bºc4
51.6 4
C
O
8a+bºc
4a 16.4
b

Answers

Answered by ramchandraverma87564

1

Answer:

gffuijhbb hgftuooihh vffuilpuu

Answered by akgupta011205

0

Answer:

a = 34 , b = 42 and c = 56

Step-by-step explanation:

by taking h.c.f a = 34,b = 42 and c = 56

I hope it was helpfull for you

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