the h. c. f. of 6x⁴y and 12xy_
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Swarup1998:
You forgot the constant numbers.
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The first term
and the second term
So, the common between the terms are
3, 2, x and y.
So, the required HCF
= 3.2.x.y
= 6xy
I HOPE THAT THIS HELPS YOU.
The first term
and the second term
So, the common between the terms are
3, 2, x and y.
So, the required HCF
= 3.2.x.y
= 6xy
I HOPE THAT THIS HELPS YOU.
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