Math, asked by surajsingh13, 1 year ago

the h. c. f. of 6x⁴y and 12xy_

Answers

Answered by Mohit0007
0
hope it helps


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Swarup1998: You forgot the constant numbers.
Mohit0007: hmm sorry bro !!!!!
Answered by Swarup1998
0
Ans.

The first term
 = 6 {x}^{4} y \\  = 3.2.x.x.x.x.y
and the second term
 = 12xy \\  = 3.2.2.x.y

So, the common between the terms are
3, 2, x and y.

So, the required HCF
= 3.2.x.y
= 6xy

I HOPE THAT THIS HELPS YOU.
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