Question

The H.C.F. of two numbers is 23 and the L.C.M. is 1449. If one of the numbers is 161, find the other number. How to do this ???

Answer 1

H.C.F*L.C.M=PRODUCT OF TWO NUMBER
23*1449=161*X
X=23*9
X=207

Answer 2

$\bf{\underline{\underline \green{Solution:-}}}$

$\frak\red{AnswEr}\begin{cases}\sf\red{\underline{The \:other\: number\:b\: = 207}}\end{cases}$

$\frak\red{Given}\begin{cases}\sf\red{\underline{H.C.F = 23}} \\ \sf\blue{\underline{L.C.M = 1449}} \\\sf\green{\underline{One\: of\: the \:number = 161}}\\\sf\orange{\underline {Unknown \: number = x }}\end{cases}$

$\frak\red{Need\:To\:Find}\begin{cases}\sf\red{\underline{The \:other\: number\: = \:?}}\end{cases}$

$\bf{\underline{\underline \green{Explanation:-}}}$

Let the two numbers be a and b.

Let the value of a be 161.

$\underline\mathtt \orange{We\:know\:that:-}$

$\bigstar\:\large{\boxed{\sf\pink{a \times b = HCF \times LCM }}}$

$\underline\mathtt \orange{Now, Putting\:the\: values:-}$

$\longrightarrow \sf {161 \times b = 23 \times 1449}$

$\longrightarrow \sf {b = 23 \times \frac{1449}{161} }$

$\longrightarrow \sf {b = \dfrac{\cancel{33327}}{\cancel{161}} }$

$\longrightarrow \sf {b = 207 }$

$\underline\mathtt \orange{Therefore:}$

• $\small\orange{\underline {\boxed{\sf\green{ The\: other \:number\: b \: is \: 207.} }}}$

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