The h.c.f of x^4-y^4 and (x^2+y^2)h
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0
Answer:
-(x2 - y2)
Step-by-step explanation:
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Answered by
0
Answer:
x²+y²
Step-by-step explanation:
x⁴-y⁴=(x²+y²)(x²-y²) {Using the identity a²-b²=(a+b)(a-b)}
=(x²+y²)(x+y)(x-y). {Using the same identity}
(x²+y²) has only 1 factor,i.e., (x²+y²)
Hence, their HCF is (x²+y²).
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