Question

The H.C.F of (x²−y²) and x³–y³ is
A.(x+y)
B.x–y
C.x²+y²+xy
D.x²–y²
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Answer 1

Answer:

B is the correct answer

Since, x2−y2=(x+y)(x−y)

x3−y3=(x−y)(x2+xy+y2)

H.C.F.=(x−y)

Option B is correct.

Answer 2

Answer-B is Correct.....