Chemistry, asked by dheemanth232010, 1 year ago

The H+ ion concentration in 0.001 M acetic acid is 1.34 into 10 to power -4 .the H+ ion concentration when 0.164g of sodium acetate is added to a litre of 0.001 M acetic acid will be​

Answers

Answered by knjroopa
34

Answer:

Explanation:

Given The H+ ion concentration in 0.001 M acetic acid is 1.34 into 10 to power -4 .the H+ ion concentration when 0.164 g of sodium acetate is added to a litre of 0.001 M acetic acid will be

H+ = 1.34 x 10^-4 in 0.001 M acetic acid

0.001 M acetic acid – 0.164 gm sodium acetate

So molecular weight = 82

Number of mole = 0.164 / 82  

                         = 0.002

So molarity of sodium acetate = 0.002

We know that Ka = 1.8 x 10^-5

Now ph = - log 1.8 x 10^-5 + log 0.002 / 0.001

          =  4.14 + 0. 3010  

         = 5.0410

Now ph = - log h+

    5.0457 = - log h+

H+ = 10^-5.0410

       = 0.00000968

     = 9 x 10^-6

Similar questions