The H+ ion concentration in 0.001 M acetic acid is 1.34 into 10 to power -4 .the H+ ion concentration when 0.164g of sodium acetate is added to a litre of 0.001 M acetic acid will be
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Explanation:
Given The H+ ion concentration in 0.001 M acetic acid is 1.34 into 10 to power -4 .the H+ ion concentration when 0.164 g of sodium acetate is added to a litre of 0.001 M acetic acid will be
H+ = 1.34 x 10^-4 in 0.001 M acetic acid
0.001 M acetic acid – 0.164 gm sodium acetate
So molecular weight = 82
Number of mole = 0.164 / 82
= 0.002
So molarity of sodium acetate = 0.002
We know that Ka = 1.8 x 10^-5
Now ph = - log 1.8 x 10^-5 + log 0.002 / 0.001
= 4.14 + 0. 3010
= 5.0410
Now ph = - log h+
5.0457 = - log h+
H+ = 10^-5.0410
= 0.00000968
= 9 x 10^-6
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