Question

The H+ion concentration of a solution is 2 x
10^-8 mol/L . The PH value of the solution is-
(log 10 2 = 0.3010)
2x 80
1 ) 7.699
2) 7.599
3) 7.799
4) 7.899 ​

Answer 1

Option 1, 7.699 is the pH of the given solution

Given Data

The [H+] concentration of a solution is 2 × 10^-8 mol/L

Also, log2 = 0.3010

The PH of a substance is the negative logarithm of the molar concentration of Hydronium ion.

$P ^H = - log_{10}[H^+]$

Now for the given solution,

$[H^+] = 2 \times {10}^{ - 8}$

So,

$P ^H = - log_{10}[H^+] \\ \\ P ^H = - log_{10}[2 \times {10}^{ - 8} ] \\ \\ P ^H = -( log_{10}(2) + log_{10}( {10}^{ - 8} ) )\\ \\ P ^H = - (0.3010 - 8) \\ \\ P ^H = 8 - 0.3010 \\ \\ P ^H = 7.6990$

Therefore, pH of the solution is 7.699, Option 1.

Answer 2

Answer:

7.699

Explanation:

This is your answer. Explaination is given above.