Question

The Haber Process synthesizes ammonia at elevated temperatures and pressures. Suppose you combine 1580 L of nitrogen gas and 4310 L of hydrogen gas at STP, heat the mixture to run the reaction, then separate the ammonia from the reaction mixture. What volume of reactant, measured at STP, is left over? Assume the reaction goes to completion. N₂ (g) + 3 H₂ (g) → 2 NH₃ (g)

Answer 1

Answer:

NH3 is the relation from nitrozzen family

Answer 2

Answer:

Volume of reaction left:-

• N2=143.33 L
• O2= 0 L

Explanation:

• At STP 1 mole of gas= 22.4 L

N₂ (g) + 3 H₂ (g) → 2 NH₃ (g)    

• Therefore in this reaction 22.4 L of N₂ (g) react completely with 3x22.4 L= 67.2 L of H₂ (g) according to there stoichiometric coefficient.

Using unitary method:-

• 67.2 L H₂ (g)of required to react with= 22.4 L of of N₂

• 1 L of H₂ (g) required to react with={(22.4 L of of N₂)/(67.2 L of H₂  )}

• 4310 L of H₂ (g) required to react with={(22.4 L of N₂)/(67.2 L)}x 4310=1436.67 L of N₂

But we are provided with 1580 L of N₂ from which only 1436.67 L reacts completely with 4310 L of H₂

Hence N₂ left =1580-1436.67=143.33 L