The haemoglobin of most mammals contains approximately 0.33% of iron by mass. The molecular mass of haemoglobin is 67200. The number of iron atoms in each molecule of haemoglobin is....... A) 3........B)4......C)2......D)6
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0.33gm of Iron in gm of Haemoglobin.
n(Fe)= 0.33/56=0.006
n(Ham)=100/67200=0.0015
This implies that in 0.0015 moles of Haemoglobin there is 0.006 moles of In Iron.
Now we have to find moles of iron in one mole of Haemoglobin so that we can find no. of Iron atoms in one mole of Haemoglobin, so from that we can find no. of atoms in one Hemoglobin molecule.
n(Fe) in one mole of Haemoglobin = 4 (from equation 1)
This implies that -
no. of Fe atoms × Na= 4× one Haemoglobin molecule ×Na
So no. of Fe atoms= 4(B).
n(Fe)= 0.33/56=0.006
n(Ham)=100/67200=0.0015
This implies that in 0.0015 moles of Haemoglobin there is 0.006 moles of In Iron.
Now we have to find moles of iron in one mole of Haemoglobin so that we can find no. of Iron atoms in one mole of Haemoglobin, so from that we can find no. of atoms in one Hemoglobin molecule.
n(Fe) in one mole of Haemoglobin = 4 (from equation 1)
This implies that -
no. of Fe atoms × Na= 4× one Haemoglobin molecule ×Na
So no. of Fe atoms= 4(B).
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