Question

The half life for a first order reaction is 5×10 6 s what percentage of the initial reactant will react vin 2 hours

Answer 1

Answer:

Here , a= initial amount of reactant. So the amount reacted is a(1–1/2^n) and hence the percentage is 100 (1–1/2^n)% . So, half-life = 5x 10^4–4 s and total time is 2 hours so n= 1.44 x 10^7 . =99.9 % .