The half life for a first order reaction is 5× 10–6.what percentage of the initial reactant will react in 2 hours
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Answer:
99.9 %
Step-by-step explanation:
Here , a= initial amount of reactant. So the amount reacted is a(1–1/2^n) and hence the percentage is 100 (1–1/2^n)% . So, half-life = 5x 10^4–4 s and total time is 2 hours so n= 1.44 x 10^7 . =99.9 % .
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