The half-life of a certain radioactive
element is such that 7/8 of a given-
quantity decay in 12days. What fraction
remains undecayed after 24 days?
a) 0
b)1/128
c)1/64
d)1/32
Answers
Answered by
17
Hello Dear,
◆ Answer -
(c) 1/64
◆ Explaination -
Let A be initial mass of the element.
In 12 days, 7/8th of A is decayed. Remaining substance will be -
A' = A - 7A/8
A' = A/8
In next 12 days, 7/8th part of A' will decay. Remaining substance will be -
A" = A' - 7A'/8
A" = A/8 - 7/8 × A/8
A" = A/8 - 7A/64
A" = A/64
Therefore after 24 days, 1/64 th part of element is remaining.
Thanks dear...
Answered by
2
Explanation:
Option C is the correct answer
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