Question

The half life of a first order reaction having rate constant k equal to 1.7 into 10 power minus 5 second inverse

Answer 1

We derive the half life of a first order reaction, as mentioned in the question above, in the following manner;

we are given with,

constant = $k$ = $1.7$ × $10^-^5$ $s^-^1$

∴ $t_1_/_2 = \frac{0.693}{k} = \frac{0.693}{1.7}$ × $10^5$ $h$ = $11.32$ $h$

Ans) The half life of a first order reaction having rate constant $k$ = $1.7$ × $10^-^5 s^-^1$ is $11.32$ $h$

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