The half life of a radioactive sample is 20 minutes the time interval t 2 - 31 between the time t2 123 of its it has declared and time t1 when 1 by 3 of its advocate is
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Answer:
N
0
=N
0
e
−λt
1
or,
3
1
N
0
=N
0
e
−λt
2
2=e
λ(t
2
−t
1
)
λ(t
2
−t
1
)=ln2
(t
2
−t
1
)=
2
ln2
=20min
3
2
N
0
=N
0
e
−λt
1
3
1
N
0
=N
0
e
−λt
2
2=e
λ(t
2
−t
1
)
λ(t
2
−t
1
)=ln2
(t
2
−t
1
)=
λ
ln2
=
Explanation:
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