The half-life of a radioactive substance is 20 days. What is the time spent between 40% decay to 85% decay of an initial number of nuclei
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k = 0.693/20
t1 = (2.303 * 20 /0.693 )log 100/60
t2 =(2.303 *20 / 0.693 ) log 100/15
final answer t1 -t2
t1 = (2.303 * 20 /0.693 )log 100/60
t2 =(2.303 *20 / 0.693 ) log 100/15
final answer t1 -t2
tinklebell6:
can you explain me more?
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