The half-life of a radioactive substance is 5 years. In how much time, 10g of this substance will reduce to 2.5g?
Answers
Answered by
3
Answer:
HII mate,
as radioactive substances are example of first order reaction, so
T1/2= 0.693/k
( T1/2 = 5 years)
k = 0.693/5
T = 2.303/k log R1/R2
= 2.303*5/ 0.693 log 10/2.5
= 2.303*5 / 0.693 log4
= 2.303 * 5 * 0.6/ 0.693 ( log 4 = 0.6)
= 9.96 = 10 years (approx.)
Similar questions