The half-life of an element is 5.8x1011. How long does it take a sample of the element to decay to 25 its original mass?
Answers
ANSWER:
Explanation: the picture above
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Explanation:
It is given:
Charcoal has the initial activity, which is denoted as A_{0}=15.3A
0
=15.3 disintegrations per minute per gram.
Charcoal has the half-life, T 12=5730T12=5730 years
After a few years, the charcoal’s final activity, A = 12.3 disintegrations per minute per gram
Constant of disintegration,
\lambda=0.693 \mathrm{T} 12=0.6935370 \mathrm{y}-1λ=0.693T12=0.6935370y−1
For the action to attain 12.3 disintegrations per minute per gram, let the time taken by the sample at a time of t year.
Sample’s activity,
A=A O e-\lambda tA=AOe−λt
A=A O e-0.6935730 \times tA=AOe−0.6935730×t
\Rightarrow \mathrm{t}=1804.3 \text { years }⇒t=1804.3 years