The half-life of Carbon-14 is 5730 years. Suppose a fossil is found with 15% of Carbon-14 as compared to a living sample. How old is the fossil? round to the nearest year
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Step-by-step explanation:
Decay constant k=
t
1/2
0.693
=
5730year
0.693
=1.209×10
−4
/years
The rate of counts is proportional to the number of C-14 atoms in the sample.
N
0
=100,N=80
The age of the sample t=
k
2.303
log(
N
N
0
)
t=
1.209×10
−4
2.303
×log(
80
100
)=1846years
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