Question

the half life period for a first order reaction is 10 sec. how much time will it take to reduce the initial concentration of its 1 by 16 th value
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Answer 1

Answer:

Hope this solution give you helps.

i forget to write the value of log2=0.3010

Answer 2

Given: half-life = 10 second

           initial concentration = N₀

           final concentration = N₀/16

To find: Time is taken to reduce the initial concentration of its 1 by 16th value

Solution:

Half life is deifned as the time taken to reduce the concentration to half.

Half-life = 10 second

N = 1/16 N₀

time-taken = 2.303× half life log [N₀/N] / 0.693

                 = 2.303×10log[2⁴] / 0.693

                 = 2.303×10×4 log2 / 0.693

                  = 40.277 second

Therefore the time required to reduce the initial concentration to its 1 by 16th value is 40.277 seconds.