The half life period for zero order reaction is 100 min. How long it will take in 80% completion
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Hey Dear,
◆ Answer -
232 min
◆ Explaination -
During 80% completion of the reaction, 100-80 = 20 % reactant will remain.
A = 20% A0
A = 0.2 A0
Rate constant is calculated by -
k = 0.693 / t½
k = 0.693 / 100
k = 0.00693 /min
Time taken for completion of reaction,
t = 2.303/k log(A0/A)
t = 2.303/0.00693 log(A0/0.2A0)
t = 2.303/0.00693 log(5)
t = 232 min
Therefore, it will take 232 min for 80 % completion of reaction.
Hope this helps you.
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