The half-life period of a first-order chemical reaction is 6.93 min. The time required for the completion of 99% of the chemical reaction will be (log
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The half-life period if the first order chemical reaction is 6.93 min. The time required for the completion of 99% of the chemical reaction will be (log2 = 0.3010):
Answered by
0
Answer:
The half life period t
1/2
=6.93 min.
The decay constant λ=
t
1/2
0.693
=
6.93min
0.693
=0.1/min
t=
λ
2.303
log
a−x
a
t=
0.1/min
2.303
log
100−99
100
t=46.06min
Hence, the time required for 99% completion of the reaction is 46.06 min
Explanation:
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