The half life period of a first order reaction is 30 minutes .How much time is required for 75% completion of the reaction ?
Answers
Answered by
3
For the first-order reaction, the relationship between the half-life period and the rate constant is
k=
t
1/2
0.693
=
30
0.693
=0.0231min
−1
.
The rate law expression is k=
t
2.303
log
(a−x)
a
.
Substitute values in the above expression.
0.0231=
70
2.303
log
(a−x)
a
log
(a−x)
a
=0.7021
(a−x)
a
=5.036
a
a−x
=
5.036
1
=0.2
Thus, the percentage of the reactant remaining after 70 min will be 20%.
Answered by
0
Explanation:
the sulphur chloride symbol
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