Question

the half life period of a radioactive element is 150days .after 600 days 1gm of the element will be reduced to​

Answer 1

Answer:

Explanation:

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Answer 2

Answer:

The element will be reduced to​ 0.0625 grams.

Explanation:

We will use the following formula to solve the question,

$\mathrm{A=\frac{A_0}{2^{n}} }$     (1)

Where,

A=the element's remaining mass after "n" half lives

A₀=intial mass of the element

n=total number of half-lives

From the question we have,

The half-life($\mathrm{t_{\frac{1}{2} }}$)=150 days

Total number of days(t)=600 days

$\mathrm{n=\frac{t}{t_{\frac{1}{2} }} }$           (2)

When the values are entered into equation (2), we obtain;

$\mathrm{n=\frac{600}{150} }$

$\mathrm{n=4}$          (3)

Equation (1) is completed by entering the values of "A₀" and "n," giving us;

$\mathrm{A=\frac{1}{2^{4}} }$

$\mathrm{A=\frac{1}{16} }$

$\mathrm{A=0.0625\ grams}$

So, the element will be reduced to​ 0.0625 grams.

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