Question

The half-life period of Actinium is 15 seconds. Starting with 0.1 g of Actinium, how much would be left at the end of one minute?​

Answer 1

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$\huge\mathfrak{Solution:-}$

⏩ Amount of Actinium left after 15 sec = 1/2 × 0.1 = 0.05 g.

Therefore,

→ Amount of Actinium left after another 15 s (i.e., 30 sec)

= 1/2 × 0.05 = 0.025 g.

→ Amount of Actinium left after another 15 s (i.e., 45 sec)

= 1/2 × 0.025 = 0.0125 g.

→Amount of Actinium left after another 15 s (i.e., 60 sec = 1 min.)

= 1/2 × 0.0125

= 0.00625 g

= 6.25 mg. Ans.

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Answer 2

Answer:

Check the attachment!!!