Question

The half life period of the body polonium 210 is about 140 days. During this period the average

no. of d-emissions per day from a mass of polonium initially equal to the 1 microgram 1s about 12

* 10, Assuming that one emission takes place per atom and that the approximate density of

polonium is 10 g em, estimate the number of atoms in 1 cm- of polonium.
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Answer 1

Answer:

sorry I do not now the answer

Answer 2

Answer:

half life(T)=140 days

Average activity during 140 days(A)=12×10^12 disintegration per day

Then,total no. of atoms disintegrated after 140 days(N-N')

=12×10^12×140=1.68×10^15 atoms

where,N is no.of atoms after 140 days

N' is no.of atoms before 140 days(initial)

so,N'/2--N'=1.68×10^15 (N=N'/2 as N is no. of atoms after one half life)

N'=3.36×10^15 atoms

WE HAVE,initial mass(m)=10^-6 gram

density (d)=10g/cc

then,initial volume (V)=m/d=10^-7 cc

NOW,

10^-7 cc contains 3.36×10^15 atoms

so,1cc contains 3.36×10^15/10^-7 atoms

=3.36×10^22 atoms

THis is the required answer.

Thanks For Reading The Answer