Question

the half life (t1/2)of first order reaction is 0.9 50 seconds what is the rate constant?

Answer 1

Answer:

The rate constant is 0.729 s⁻¹.

Explanation:

Given,

The half-life ( $t_{1/2}$ ) = 0.95 sec

To find,

the rate constant (k)

Concept,

A first-order reaction may be described as a chemical reaction in which the reaction rate is linearly depending on the concentration of only one reactant

Rate = -d[A]/dt = k[A]¹ = k[A]

Where

‘k’ is the rate constant.

‘[A]’ denotes the concentration of the first-order reactant ‘A’.

d[A]/dt denotes the change in the concentration of the reactant ‘A’ in the time interval ‘dt’.

Calculation,

We know that:

Half-life of first-order reaction ( $t_{1/2}$ ) = 0.693/k

$\implies k = \frac{0.693}{t_{1/2}}$

$\implies k = \frac{0.693}{0.95}$

$\implies k = 0.729 s^{-1}$

Therefore, the rate constant is 0.729 s⁻¹.

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Answer 2

Answer:

The rate constant is $0.729s^{-1}$.

Explanation:

It is given that half life is $0.95 sec$

A first-order reaction is a chemical reaction in which the reaction rate is linearly depending on the concentration of only one reactant.

Mathematically

$R=-k\frac{dA}{dt} =k[A]^{-1} =k[A]$

Half life $=\frac{0.693}{k}$

Putting values

$k=\frac{0.693}{0.95}$

$k=0.729s^{-1}$

Rate constant is $0.729s^{-1}$

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