The half lives of a first order reaction at 20 and 30° Care 18 and 9 minutes respectively, Calculate the energy of activation.
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Explanation:
The half life period of a first order reaction is 20 minutes.
t
1/2
=20 minutes.
The rate constant, k=
t
1/2
0.693
=
20min
0.693
=0.03465/min
The time required for the concentration of the reactant to change from 0.16M to 0.02M
is t=
k
2.303
log
a−x
a
=
0.03465/min
2.303
log
0.02
0.16
=60min
i hope it's helpful for you
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