the half time period of a second order reaction is 90 minutes calculate the time required for its 60% completion
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Given :-
Reaction time for second order = 90 minutes.
Time required = ?
We know the formula ,
90 =
K =
k = 0.0001111
Now , we know remaining reactant is 40 % so,
1/40 = 1/100 + 0.00011 t
1.1 × 10⁻⁴ t = 1/40 - 1/100
t = 0.015 / 1.11 × 10⁻⁴
t = 136.3 minutes.
Hence time required for the 60% completion is 136.3 minutes.
Hope it Helps.
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