Question

The hallat onder reaction having rate constant k = 1.7 x 10 secs
a) 12-16
b) 9.7 hr
c) 11.3 hr
d)1.8 hr​

Answer 1

c)11.3

t1/2 = k

ln 2

= 1.7×10 −5

0.693

=40764 sec= 40764/3600 hrs=11.3 hrs.