.
The hand-bore well dealer charges Rs 200.- for the first one metre only and raises drilling
charges at the rate of rupees 30/- for every subsequent metre. Write a progression for the
above data
Answers
A progression for the above data = 200,230,260,290...............
Given:
The hand-bore well dealer charges Rs 200.
For the first one meter only and raises drilling .
Charges at the rate of rupees 30/- for every subsequent meter.
To find:
A progression for the above data.
Explanation:
For first the hand-bore well dealer charges Rs 200.
Charges at the rate of rupees 30/- for every subsequent meter.
That is for second meter charge is equal to rupees 30/- more than first meter.
Second meter charge = 200+30 = 230
Third meter charge is equal to rupees 30/- more than second meter.
Third meter charge = 230+30 = 260 Rs
So on......
A progression for the above data = 200,230,260,290...............
This is arithmetic progression with common difference = 30
To learn more...
1)Sum of three consecutive terms of an Arithmetic Progression is 42 and their product is 2520.
https://brainly.in/question/11255431
2)Measures of sides of a triangle are in Arithmetic progression. Its perimeter is 30 cm, and the
between the longest and shortest side is 4 cm, then find the meqasure of the sides
https://brainly.in/question/13742618
Answer:
For progression first term a and common difference d is required.
Progression will be t
n
=a+(n−1)d
As for the first one metre charges are Rs.200 and Rs.30 for subsequent metre.
therefore a=200 and d=30
So progression t
n
=200+(n−1)30 where n=1,2,3..
hope it helps