Question

The handle of a nut craker is 18cm long and a nut is placed 2cm from its hinge.If a force of 36kgf is placedon the nut,it will crack.Calculate the force which has to be applied at the end of the handle to crack the nut

Answer 1

Given,

Force = 36 Kgf
Distance = (18+2) cm = 20 cm
Distance = 20/100 m = 0.2 m

As we know that,
Torque is a turning force.
Here we will apply Torque.

Torque = Fd

=> T = (36 x 0.2) N-m

=> T = 7.2 N-m


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