Question

the handle of a nutcracker is 18 cm long and a nut is placed 2 cm from its hinge. if a force of 36 kgf is placed on the nut , it will crack calculate the force which has to be applied at the end of the handle to crack the nut

Answer 1

Answer:

4kgf

Explanation:

Load = 36 kgf

Load arm = 2 cm Effort = ?

Effort arm =18 cm

Load x load arm = Effort x Effort arm 36 kgf x 2 cm = Effort x 18 cm

Effort = (36 * 2)/18

Effort = 4 kgf

Thus, to crack the nut the force of 4kgf must be applied at the end of the handle.

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