Question

the handle of a nutcracker is 18cm long and a nut is placed 2cm from its hinge . if a force of 36kgf is placed on the nut , it will crack. calculate the force which has to be applied at the end of the handle to crack the nut.​

Answer 1

Distance of nut from fulcrum (d) = 2 cm

Distance of effort from fulcrum (D) = 18 cm

Load × Load arm = Effort × Effort arm

Load × 2 cm = 36 kgf × 18 cm

Load = 324 kgf

Answer 2

Distance of nut from fulcrum (d) = 2 cm

Distance of effort from fulcrum (D) = 18 cm

Load × Load arm = Effort × Effort arm

Load × 2 cm = 36 kgf × 18 cm

Load = 324 kgf

Hope it helps you