The handle of a water pump is 90 cm long from its piston rod . If the pivot of handle is at a distance of 15 cm from piston rod , calculate a) least effort required at its other end to overcome a resistance of 60 kgf and b ) mechanical advantage of handle .
Sixth Standard . Numericals
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Let's first calculate mechanical advantage.
Load arm =15 cm
Effort arm = handle of water pump - load arm = 90 - 15 = 75 cm
MA = Effort arm/load arm = 75/15 = 5
Thus, effort required to overcome resistance or load of 60 kgf is,
MA = Load/Effort
Thus,
Effort = load/ MA = 60 kgf/5 = 12 kgf
Thus, effort = 12 kgf
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